İKİ NOKTASI BİLİNEN DOĞRU DENKLEMİ KONU ANLATIMI

AD =x2−x1

BD =y2−y1

CE =x2−x

BE =y2−y

tanθ=BDAD

⇒tanθ=y2−y1x2−x1

⇒(y2−y1).(x2−x)=(y2−y).(x2−x1)

⇒y2.x2−y2.x−y1.x2+y1.x=y2.x2−y2.x1−y.x2+y.x1

⇒y2.x2−y2.x−y1.x2+y1.x−y2.x2+y2.x1+y.x2−y.x1=0

−y2.x+y1.x+y.x2−y.x1−y1.x2+y2.x1+y2.x2−y2.x2=0

−y2.x+y1.x+y.x2−y.x1−y1.x2+y2.x1=0

(−y2+y1)x+(x2−x1)y+(−y1.x2+y2.x1)=0